Topic 05 Practice Test 2 covers Wireless Principles, Virtualization, and Switching Concepts for Cisco Certified Network Associate 200-301 CCNA and maps to objectives 1.11–1.13. For broader exam preparation, review the Cisco CCNA 200-301 Exam Dumps. Every option includes focused technical reasoning explaining both the networking concept and its fit to the scenario.
Question 1
Operations at Meadowpark asks Yara to validate Unity before approving change CHG-4220. A warehouse RF survey must assign three adjacent 2.4-GHz AP cells to 20-MHz channels without adjacent-channel overlap. Which three-channel reuse plan is appropriate in the U.S.? Choose ONE.
- Channels 3, 6, and 9
- Channels 1, 6, and 11
- Channels 1, 4, and 8
- Channels 2, 7, and 12
Correct Answer: B
Correct Answer
Answer B is correct because In the 2.4-GHz band, Cisco guidance identifies 1, 6, and 11 as the three nonoverlapping 20-MHz channels used for a basic channel reuse plan. Assigning those three channels to adjacent cells minimizes adjacent-channel overlap compared with plans that use intermediate channel numbers. In the Operations Meadowpark Yara validation, this distinction is directly relevant.
Incorrect Answers
Answer C is incorrect because Channels 4 and 8 overlap neighboring 20-MHz channels in the 2.4-GHz band. That plan creates adjacent-channel interference instead of using the established nonoverlapping set. The scenario requires for this interface,, a different property for this prefix,,, so this alternative must be rejected.
Answer D is incorrect because These channel centers are offset from the standard 1/6/11 reuse plan and overlap other 2.4-GHz 20-MHz channels. They are not the nonoverlapping three-channel plan requested for the office. This condition is observable in the resulting interface, addressing, or forwarding state. In the Operations Meadowpark Yara validation, this distinction is directly relevant.
Answer A is incorrect because Although channel 6 is in the standard set, channels 3 and 9 overlap neighboring 20-MHz channels. The three APs would therefore contend with adjacent-channel energy rather than operating on separate nonoverlapping channels. It would either for this packet,, misaddress the interface or describe the wrong network behavior.
Question 2
The Boreal deployment at Ridgeview has reached its verification gate; Eva is handling CHG-4233. Help-desk staff are onboarding users to a WLAN named CORP-EAST. Which wireless field is the human-readable network name clients select? Choose ONE.
- RF channel width
- Encryption cipher
- SSID
- BSSID
Correct Answer: C
Correct Answer
Answer C is correct because The service set identifier is the logical WLAN name advertised or configured for clients and is what users commonly see when selecting a wireless network. A corporate SSID therefore provides the human-readable identity requested in the scenario. In the The Boreal Ridgeview validation, this distinction is directly relevant.
Incorrect Answers
Answer D is incorrect because A BSSID identifies a specific basic service set, commonly corresponding to an AP radio MAC address rather than the user-facing WLAN name. It is useful for distinguishing radios/cells but is not the requested human-readable network identifier. It would either in this VLAN,, misaddress the interface on this device,, or describe the wrong network behavior.
Answer A is incorrect because Channel width describes how much radio spectrum a transmission occupies, such as 20 or 40 MHz. It affects RF operation and throughput but does not name the WLAN for users. That mismatch makes in this context,, it unsuitable even, for this packet for this host,,, though it may be valid elsewhere.
Answer B is incorrect because A cipher protects wireless frame confidentiality and integrity but is not the network name. Security and identification are separate properties, so the cipher cannot replace the SSID. Using it would, for this route for this prefix,,, leave the key addressing or forwarding requirement unsatisfied.
Question 3
At the Stonebridge office, Priya checks a Impulse design assumption while processing CHG-4246. A handheld scanner works near an AP at -48 dBm but falls to -78 dBm after the user moves behind reinforced walls, while airtime use remains low. Which RF effect best explains the change? Choose ONE.
- SSID mismatch
- MAC address aging
- VRF route separation
- Attenuation through obstacles
Correct Answer: D
Correct Answer
Answer D is correct because RF energy is reduced as it propagates through distance and materials such as concrete; more-negative dBm values represent weaker received power. The large drop in received signal after moving behind walls is therefore consistent with attenuation. In the At Stonebridge Priya validation, this distinction is directly relevant.
Incorrect Answers
Answer A is incorrect because An SSID identifies the WLAN but does not physically reduce received RF power as a client moves behind obstacles. A mismatch could prevent association, but it would not explain the measured dBm change. Using it would in this check,, leave the key in this context,, addressing or forwarding requirement unsatisfied.
Answer B is incorrect because MAC aging removes inactive Layer 2 forwarding entries from a switch table after a timer expires. That forwarding-table behavior does not alter radio signal strength at the wireless receiver. The requested outcome follows from the protocol rule being exercised in this scenario.
Answer C is incorrect because A VRF separates Layer 3 routing/forwarding tables on a network device. Routing-table separation has no direct effect on RF energy received through concrete walls. This result can be confirmed from the address, interface, or forwarding information provided.
Question 4
Change CHG-4259 covers the Pioneer network at Clearview, where Noah is the assigned verifier. A security review requires confidentiality for 802.11 frames while they travel between clients and the AP. Which wireless property addresses that requirement? Choose ONE.
- Encryption
- SSID naming
- Channel selection
- MAC aging
Correct Answer: A
Correct Answer
Answer A is correct because Wireless encryption transforms protected frame contents so an observer without the appropriate key cannot simply read the traffic. That directly addresses confidentiality on the RF medium. That distinction prevents a valid-looking alternative from meeting the actual requirement.
Incorrect Answers
Answer B is incorrect because An SSID identifies a WLAN and helps clients select it. Changing or hiding the name does not cryptographically protect frame contents from interception. The device evaluates this property directly when it performs the relevant lookup or interface operation.
Answer C is incorrect because Choosing channels helps manage RF interference and capacity. It can improve reliability but does not make captured frame payloads confidential. That behavior is consistent with the configuration evidence supplied in the question.
Answer D is incorrect because MAC aging manages stale forwarding-table entries on switches. It neither encrypts wireless traffic nor prevents an RF observer from capturing frames. That mismatch makes in this context,, it unsuitable even on this device,, though it may be valid elsewhere.
Question 5
At Bayfront, Hana validates the Willow cutover under change CHG-4272. Three neighboring 2.4-GHz APs were placed on channels 2, 3, and 4 and users report interference despite adequate signal strength. Which change best corrects the channel plan? Choose ONE.
- Place all AP management interfaces in one VRF
- Move the APs to a reuse plan based on channels 1, 6, and 11
- Rename each SSID to a shorter value
- Increase MAC address aging time
Correct Answer: B
Correct Answer
Answer B is correct because Channels 1, 2, and 3 overlap heavily in 2.4 GHz, so neighboring cells contend with and interfere with one another. Using the standard nonoverlapping 1/6/11 set reduces adjacent-channel overlap and better matches enterprise RF design guidance. In the At Bayfront Hana validation, this distinction is directly relevant.
Incorrect Answers
Answer C is incorrect because SSID length does not change the RF channel overlap between adjacent access points. The performance problem is caused by channel placement, not by the human-readable WLAN names. That mismatch makes on this link,, it unsuitable even in this design,, though it may be valid elsewhere.
Answer D is incorrect because MAC aging affects wired Layer 2 forwarding-table retention. Changing that timer does not separate overlapping 2.4-GHz RF channels. Using it would in this check,, leave the key for this address,, addressing or forwarding requirement unsatisfied.
Answer A is incorrect because A VRF controls Layer 3 routing-table separation for IP traffic. It does not change the spectrum used by AP radios or eliminate adjacent-channel interference. The scenario requires a different property in this WLAN,,, so this alternative must be rejected.
Question 6
The Delta migration at Highpoint is in pre-check, and Adil owns ticket CHG-4285. A test lab must run Windows, Linux, and two legacy appliance operating systems concurrently on one physical server, with each guest administered independently. Which approach fits? Choose ONE.
- MAC address aging
- A wireless SSID
- Server virtualization with virtual machines
- A single Layer 2 VLAN
Correct Answer: C
Correct Answer
Answer C is correct because A hypervisor abstracts the physical server and presents isolated virtual hardware to multiple virtual machines, each of which can run its own guest operating system. That directly matches the requirement for independent guest OS instances sharing one physical host. In the The Delta Highpoint validation, this distinction is directly relevant.
Incorrect Answers
Answer D is incorrect because A VLAN partitions a switched Layer 2 broadcast domain but does not create virtual CPUs, memory, disks, or guest operating systems. Network segmentation alone cannot satisfy the server-compute virtualization requirement. The scenario requires for this interface,, a different property for this prefix,,, so this alternative must be rejected.
Answer A is incorrect because MAC aging controls how long dynamic Layer 2 forwarding entries remain in a switch table. It has no role in creating isolated guest operating systems on a physical server. This distinction is what an engineer would verify from the resulting device state.
Answer B is incorrect because An SSID identifies a wireless LAN to clients. It can map users into a network but does not virtualize server hardware or operating systems. It would either for this packet,, misaddress the interface or describe the wrong network behavior.
Question 7
During Elmwood’s Comet maintenance window, Luca performs the network acceptance test for CHG-4298. A build platform needs isolated application environments that start in seconds and reuse the host kernel instead of booting a guest OS for every job. Which technology fits? Choose ONE.
- Traditional virtual machines only
- VRF instances
- Ethernet MAC tables
- Containers
Correct Answer: D
Correct Answer
Answer D is correct because Containers isolate application processes and dependencies while sharing the host kernel, which reduces overhead compared with a full guest operating system per workload. That lightweight execution model matches the stated startup and kernel-sharing requirements. In the During Elmwood Comet validation, this distinction is directly relevant.
Incorrect Answers
Answer A is incorrect because A VM commonly includes a separate guest operating system above a hypervisor. That offers strong OS-level isolation but does not match the requirement to share the host kernel and avoid a guest OS per instance. In the During Elmwood Comet validation, this distinction is directly relevant.
Answer B is incorrect because VRFs create separate Layer 3 routing and forwarding tables within a network device. They isolate network routing domains rather than packaging application processes and dependencies. That mismatch makes in this context,, it unsuitable even, for this packet for this host,,, though it may be valid elsewhere.
Answer C is incorrect because MAC tables map destination MAC addresses to switch ports for Layer 2 forwarding. They provide switching state, not application workload isolation. Using it would, for this route for this prefix,,, leave the key addressing or forwarding requirement unsatisfied.
Question 8
For ticket CHG-4311, Cleo is reviewing the Jade rollout at the Kingsway site. A provider edge router serves two customers that both advertise 10.10.10.0/24. Which feature keeps their Layer 3 routing tables independent on the same device? Choose ONE.
- VRF
- SSID
- MAC address aging
- Channel bonding
Correct Answer: A
Correct Answer
Answer A is correct because Virtual Routing and Forwarding creates separate routing and forwarding table instances on one Layer 3 device and can allow overlapping IP address space in different routing domains. That directly lets the two tenants use the same prefix without merging their routes. In the For CHG-4311 Cleo validation, this distinction is directly relevant.
Incorrect Answers
Answer B is incorrect because An SSID identifies a wireless LAN and may map wireless clients to other network constructs. It does not by itself create independent Layer 3 routing tables for overlapping tenant prefixes. The scenario therefore hinges on the specific protocol behavior, not merely on a plausible value.
Answer C is incorrect because MAC aging removes inactive Layer 2 forwarding entries after a timer. It cannot isolate overlapping Layer 3 routes or create tenant-specific routing tables. The network behavior is determined by this rule when the stated values are applied.
Answer D is incorrect because Wireless channel bonding combines spectrum to increase potential PHY throughput. It is an RF capacity feature and has no connection to routing-table virtualization. This is the property an engineer would confirm during an implementation or troubleshooting check.
Question 9
Before Parkside hands the Quartz service to operations, Sofia must close verification item CHG-4324. Traffic arrives on an interface in VRF BLUE. The global routing table has a route to the destination, but BLUE does not. Why is that global route not used automatically? Choose ONE.
- SSID encryption blocks the route
- VRFs maintain separate routing and forwarding contexts
- Unknown unicasts are always flooded across VRFs
- Containers replace routing tables
Correct Answer: B
Correct Answer
Answer B is correct because A VRF associates interfaces with an independent routing/forwarding table, so a packet arriving in that context is looked up against the VRF unless explicit route leaking is configured. The global table is therefore not automatically consulted merely because it has a route. In the Before Parkside Quartz validation, this distinction is directly relevant.
Incorrect Answers
Answer C is incorrect because Unknown-unicast flooding is a Layer 2 behavior within a VLAN when a destination MAC is absent from the table. It does not cause Layer 3 packets to ignore VRF routing-table separation. In the Before Parkside Quartz validation, this distinction is directly relevant.
Answer D is incorrect because Containers isolate application workloads and do not inherently merge or replace router forwarding contexts. They cannot explain why a VRF lookup stays separate from the global routing table. The relevant state can be verified from the protocol information and configuration described here.
Answer A is incorrect because Wireless encryption protects frames over the RF medium. It has no role in selecting a router forwarding table for a packet already received on a VRF interface. The alternative fails because the operational result differs from what the scenario explicitly requires.
Question 10
A peer review for Xenon at Willowbrook assigns Samir the evidence check recorded as CHG-4337. Four acquired applications each require their original operating system, but the data center wants to retire four physical servers and use one larger host. Which virtualization benefit enables this? Choose ONE.
- The switch floods every destination MAC
- The AP advertises multiple SSIDs
- Multiple isolated virtual machines can share one physical server
- All applications must share one kernel namespace
Correct Answer: C
Correct Answer
Answer C is correct because Server virtualization abstracts CPU, memory, storage, and network resources so several VMs can coexist while retaining separate guest operating systems. That enables consolidation without forcing the legacy applications into one shared OS instance. In the A Xenon Willowbrook validation, this distinction is directly relevant.
Incorrect Answers
Answer D is incorrect because Sharing one host kernel is characteristic of container-style isolation, not a requirement for independent legacy guest operating systems. It would conflict with the stated need to preserve each application server operating system. In the A Xenon Willowbrook validation, this distinction is directly relevant.
Answer A is incorrect because Unknown-unicast flooding is a switching fallback when a destination MAC is not learned. It does not consolidate compute workloads or preserve separate guest operating systems. The protocol rule makes this distinction observable during configuration validation and troubleshooting.
Answer B is incorrect because Multiple SSIDs can provide distinct WLANs on wireless infrastructure. That is network-service virtualization, not server consolidation of independent operating systems. The correct choice aligns both with the configured state and with the resulting network behavior.
Question 11
The Ashford branch is staging Ember; Mina is completing the implementation checklist for CHG-4350. After a switch reboot, the MAC table is empty. A frame enters Gi1/0/7 in VLAN 30 with source 00:11:22:33:44:55. What dynamic entry should the switch create? Choose ONE.
- Destination MAC is reachable through Gi1/0/7
- The IPv4 default gateway is Gi1/0/7
- The SSID for VLAN 30 is Gi1/0/7
- Source MAC 00:11:22:33:44:55 is reachable through Gi1/0/7 in VLAN 30
Correct Answer: D
Correct Answer
Answer D is correct because Ethernet switches populate their MAC address tables from the source MAC address of received frames, associating that source with the ingress port and VLAN. The received frame therefore teaches the switch where to send future frames destined to that source MAC. In the The Ashford Ember validation, this distinction is directly relevant.
Incorrect Answers
Answer A is incorrect because A switch does not learn a destination location merely because a frame naming that destination arrived on another port. Dynamic learning is based on the source MAC observed on the ingress interface. In the The Ashford Ember validation, this distinction is directly relevant.
Answer B is incorrect because Default gateways are Layer 3 next-hop addresses configured on hosts or represented by routed interfaces. A Layer 2 source-MAC observation does not create a default-gateway setting. This difference is important because the same device can treat otherwise similar values in different ways.
Answer C is incorrect because An SSID is a wireless LAN identifier and is not learned from an Ethernet frame source address. The switching decision here concerns MAC-to-port learning in a VLAN, not wireless naming. The implementation must match this protocol property to satisfy the scenario’s requirement.
Question 12
As part of Lantern readiness at Briarwood, Ben investigates the condition logged in CHG-4363. A VLAN 20 switch already maps destination 00:aa:bb:cc:dd:ee to Gi1/0/18. A matching unicast frame arrives on Gi1/0/4. Which forwarding action is expected? Choose ONE.
- Forward the frame only toward Gi1/0/18
- Flood the frame to every forwarding port in VLAN 20
- Route the frame using the default gateway
- Drop the frame because it arrived on Gi1/0/4
Correct Answer: A
Correct Answer
Answer A is correct because For a known unicast destination, the switch looks up the destination MAC in the VLAN-specific table and forwards the frame out the associated port. Because the destination is already learned on Gi1/0/18, flooding is unnecessary. In the As Lantern Briarwood validation, this distinction is directly relevant.
Incorrect Answers
Answer B is incorrect because Flooding is used for certain broadcast, multicast, or unknown-unicast conditions rather than for a valid known-unicast entry. The switch already knows the destination port, so sending copies everywhere would be unnecessary. In the As Lantern Briarwood validation, this distinction is directly relevant.
Answer C is incorrect because Same-VLAN Layer 2 forwarding uses the MAC table and does not require a router simply because the frame traverses a switch. The destination is known locally at Layer 2. This is the relevant behavior an administrator would confirm before accepting the change.
Answer D is incorrect because A frame is not dropped merely because its ingress port differs from the learned destination port. That difference is normal and tells the switch which egress interface to use. The scenario tests that exact distinction as it would appear during a practical verification workflow.
Question 13
Operations at Copperfield asks Arun to validate Signal before approving change CHG-4376. A server sends a unicast frame in VLAN 40 to a destination not yet present in the switch MAC table. How does ordinary Layer 2 switching handle the unknown destination? Choose ONE.
- Consult the DNS server for the MAC address
- Flood the frame out other forwarding ports in VLAN 40
- Send the frame to every port in every VLAN
- Discard every unknown unicast by default
Correct Answer: B
Correct Answer
Answer B is correct because When a unicast destination is unknown, the switch floods the frame within the same VLAN except back out the ingress port, allowing the destination to receive it if present. A reply then gives the switch an opportunity to learn the destination station as a source. In the Operations Copperfield Arun validation, this distinction is directly relevant.
Incorrect Answers
Answer C is incorrect because VLANs define separate Layer 2 broadcast domains and MAC-table contexts. Unknown-unicast flooding stays within the frame VLAN rather than crossing all VLANs on the switch. This is the relevant behavior an administrator would confirm before accepting the change.
Answer D is incorrect because Ordinary Ethernet switching normally floods an unknown unicast rather than discarding it outright. Dropping would prevent communication with a legitimate station whose MAC entry has not yet been learned or has aged out. In the Operations Copperfield Arun validation, this distinction is directly relevant.
Answer A is incorrect because DNS resolves names to IP addresses and is not used by a switch to locate an unknown Layer 2 destination. The switch relies on flooding and subsequent source-MAC learning instead. The expected result follows from the device state and protocol semantics given in the question.
Question 14
The Zodiac deployment at Foxglove has reached its verification gate; Leo is handling CHG-4389. A printer’s dynamic MAC entry has expired after a long idle period. Before the printer transmits again, a host sends it a unicast frame. How will the switch treat that destination? Choose ONE.
- The switch creates a new IPv4 route
- The switch changes the workstation SSID
- The destination is treated as unknown and the frame is flooded within the VLAN
- The old port mapping is retained permanently
Correct Answer: C
Correct Answer
Answer C is correct because Aged dynamic entries are removed from the MAC table; until the destination is learned again, the switch has no specific egress port for that MAC. The first subsequent unknown-unicast frame is therefore flooded within the VLAN, excluding the ingress port. In the The Zodiac Foxglove validation, this distinction is directly relevant.
Incorrect Answers
Answer D is incorrect because Dynamic MAC entries are specifically designed to age out after inactivity unless configured as static. The scenario states the entry has expired, so the switch cannot keep using that stale mapping as if it were permanent. In the The Zodiac Foxglove validation, this distinction is directly relevant.
Answer A is incorrect because MAC aging operates at Layer 2 and does not add entries to the IP routing table. The forwarding fallback is a Layer 2 flood, not creation of a Layer 3 route. In the The Zodiac Foxglove validation, this distinction is directly relevant.
Answer B is incorrect because An SSID is a wireless service identifier and is not derived from wired MAC-table aging. Aging only changes whether the switch remembers the MAC-to-port association. The engineer must match the requested behavior, not just choose a value that is generally valid elsewhere.
Question 15
At the Granite office, Lina checks a Gateway design assumption while processing CHG-4402. A frame enters a switch port and the destination MAC is already learned on that same ingress port. What is the normal Layer 2 action? Choose ONE.
- Flood it to all other VLANs
- Send it to the default gateway
- Replace the destination MAC with the source MAC
- Filter it instead of forwarding it back out the same port
Correct Answer: D
Correct Answer
Answer D is correct because A switch uses the destination MAC table entry to select an egress port; when the known destination is on the same port as the source segment, forwarding the frame back to that port is unnecessary. Filtering avoids an invalid same-port retransmission. In the At Granite Lina validation, this distinction is directly relevant.
Incorrect Answers
Answer A is incorrect because VLAN boundaries isolate Layer 2 forwarding domains, and a known same-port destination is not an unknown-unicast event. Flooding other VLANs would violate normal switching behavior. This criterion is what separates the correct operational result from the other plausible alternatives.
Answer B is incorrect because A known same-segment Layer 2 destination does not require Layer 3 routing. The switch can decide locally from its MAC table and should not redirect the frame to a gateway. The network device applies this rule consistently when processing the described configuration or traffic.
Answer C is incorrect because Layer 2 switching forwards frames according to learned addresses; it does not rewrite the destination address merely because ingress and learned egress match. The correct behavior is filtering, not address substitution. In the At Granite Lina validation, this distinction is directly relevant.
Question 16
Change CHG-4415 covers the Falcon network at Hawthorne, where Caleb is the assigned verifier. A training center is redesigning 2.4-GHz coverage and wants the familiar three-channel plan that avoids adjacent-channel overlap in the U.S. Which set is appropriate? Choose ONE.
- Channels 1, 6, and 11
- Channels 1, 4, and 8
- Channels 2, 7, and 12
- Channels 3, 6, and 9
Correct Answer: A
Correct Answer
Answer A is correct because In the 2.4-GHz band, Cisco guidance identifies 1, 6, and 11 as the three nonoverlapping 20-MHz channels used for a basic channel reuse plan. Assigning those three channels to adjacent cells minimizes adjacent-channel overlap compared with plans that use intermediate channel numbers. In the Change CHG-4415 Falcon validation, this distinction is directly relevant.
Incorrect Answers
Answer B is incorrect because Channels 4 and 8 overlap neighboring 20-MHz channels in the 2.4-GHz band. That plan creates adjacent-channel interference instead of using the established nonoverlapping set. The outcome is determined by the stated addressing or forwarding condition rather than by naming convention.
Answer C is incorrect because These channel centers are offset from the standard 1/6/11 reuse plan and overlap other 2.4-GHz 20-MHz channels. They are not the nonoverlapping three-channel plan requested for the office. The operational outcome follows directly from the configuration and protocol behavior described here.
Answer D is incorrect because Although channel 6 is in the standard set, channels 3 and 9 overlap neighboring 20-MHz channels. The three APs would therefore contend with adjacent-channel energy rather than operating on separate nonoverlapping channels. In the Change CHG-4415 Falcon validation, this distinction is directly relevant.
Question 17
At Ironwood, Clara validates the Meteor cutover under change CHG-4428. A campus core carries two lab environments with overlapping 10.1.0.0/16 space. Each environment requires an independent routing table on the same switch. Which feature fits? Choose ONE.
- Channel bonding
- VRF
- SSID
- MAC address aging
Correct Answer: B
Correct Answer
Answer B is correct because Virtual Routing and Forwarding creates separate routing and forwarding table instances on one Layer 3 device and can allow overlapping IP address space in different routing domains. That directly lets the two tenants use the same prefix without merging their routes. In the At Ironwood Clara validation, this distinction is directly relevant.
Incorrect Answers
Answer C is incorrect because An SSID identifies a wireless LAN and may map wireless clients to other network constructs. It does not by itself create independent Layer 3 routing tables for overlapping tenant prefixes. That behavior is consistent with the configuration evidence supplied in the question. In the At Ironwood Clara validation, this distinction is directly relevant.
Answer D is incorrect because MAC aging removes inactive Layer 2 forwarding entries after a timer. It cannot isolate overlapping Layer 3 routes or create tenant-specific routing tables. That makes the option unsuitable for this specific verification goal even if it is valid in another context.
Answer A is incorrect because Wireless channel bonding combines spectrum to increase potential PHY throughput. It is an RF capacity feature and has no connection to routing-table virtualization. This matters during verification because the configured value determines the device behavior being tested.
Question 18
The Tangent migration at Lakeview is in pre-check, and Dina owns ticket CHG-4441. After a CAM entry expires, a host sends a unicast frame to that now-unknown destination in VLAN 70. What does the switch normally do? Choose ONE.
- Discard every unknown unicast by default
- Consult the DNS server for the MAC address
- Flood the frame out other forwarding ports in VLAN 40
- Send the frame to every port in every VLAN
Correct Answer: C
Correct Answer
Answer C is correct because When a unicast destination is unknown, the switch floods the frame within the same VLAN except back out the ingress port, allowing the destination to receive it if present. A reply then gives the switch an opportunity to learn the destination station as a source. In the The Tangent Lakeview validation, this distinction is directly relevant.
Incorrect Answers
Answer D is incorrect because VLANs define separate Layer 2 broadcast domains and MAC-table contexts. Unknown-unicast flooding stays within the frame VLAN rather than crossing all VLANs on the switch. The operational distinction is visible in the resulting interface, address, or forwarding state.
Answer A is incorrect because Ordinary Ethernet switching normally floods an unknown unicast rather than discarding it outright. Dropping would prevent communication with a legitimate station whose MAC entry has not yet been learned or has aged out. In the The Tangent Lakeview validation, this distinction is directly relevant.
Answer B is incorrect because DNS resolves names to IP addresses and is not used by a switch to locate an unknown Layer 2 destination. The switch relies on flooding and subsequent source-MAC learning instead. A correct implementation must satisfy that property rather than a superficially similar one.
Question 19
During Millstone’s Aurora maintenance window, Jamal performs the network acceptance test for CHG-4454. Developers need portable application packages that isolate dependencies but share the host kernel to reduce startup overhead. Which technology should they use? Choose ONE.
- Traditional virtual machines only
- VRF instances
- Ethernet MAC tables
- Containers
Correct Answer: D
Correct Answer
Answer D is correct because Containers isolate application processes and dependencies while sharing the host kernel, which reduces overhead compared with a full guest operating system per workload. That lightweight execution model matches the stated startup and kernel-sharing requirements. In the During Millstone Aurora validation, this distinction is directly relevant.
Incorrect Answers
Answer A is incorrect because A VM commonly includes a separate guest operating system above a hypervisor. That offers strong OS-level isolation but does not match the requirement to share the host kernel and avoid a guest OS per instance. In the During Millstone Aurora validation, this distinction is directly relevant.
Answer B is incorrect because VRFs create separate Layer 3 routing and forwarding tables within a network device. They isolate network routing domains rather than packaging application processes and dependencies. The requested outcome follows from the protocol rule being exercised in this scenario. In the During Millstone Aurora validation, this distinction is directly relevant.
Answer C is incorrect because MAC tables map destination MAC addresses to switch ports for Layer 2 forwarding. They provide switching state, not application workload isolation. This condition is observable in the resulting interface, addressing, or forwarding state.
Question 20
For ticket CHG-4467, Eli is reviewing the Horizon rollout at the Newbridge site. Switch SW1 receives a frame on Gi1/0/22 in VLAN 90 from source MAC 0c:11:22:33:44:55. What mapping is learned? Choose ONE.
- Source MAC 0c:11:22:33:44:55 is reachable through Gi1/0/22 in VLAN 90
- Destination MAC is reachable through Gi1/0/7
- The IPv4 default gateway is Gi1/0/7
- The SSID for VLAN 30 is Gi1/0/7
Correct Answer: A
Correct Answer
Answer A is correct because Ethernet switches populate their MAC address tables from the source MAC address of received frames, associating that source with the ingress port and VLAN. The received frame therefore teaches the switch where to send future frames destined to that source MAC. In the For CHG-4467 Eli validation, this distinction is directly relevant.
Incorrect Answers
Answer B is incorrect because A switch does not learn a destination location merely because a frame naming that destination arrived on another port. Dynamic learning is based on the source MAC observed on the ingress interface. In the For CHG-4467 Eli validation, this distinction is directly relevant.
Answer C is incorrect because Default gateways are Layer 3 next-hop addresses configured on hosts or represented by routed interfaces. A Layer 2 source-MAC observation does not create a default-gateway setting. The scenario requires that exact behavior rather than a generally related network concept.
Answer D is incorrect because An SSID is a wireless LAN identifier and is not learned from an Ethernet frame source address. The switching decision here concerns MAC-to-port learning in a VLAN, not wireless naming. That distinction prevents a valid-looking alternative from meeting the actual requirement.
