Cisco CCNA 200-301 Wireless Principles, Virtualization, and Switching Concepts Practice Test 3

 

Topic 05 Practice Test 3 covers Wireless Principles, Virtualization, and Switching Concepts for Cisco Certified Network Associate 200-301 CCNA and maps to objectives 1.11–1.13. For broader exam preparation, review the Cisco CCNA 200-301 Exam Dumps. Every option includes focused technical reasoning explaining both the networking concept and its fit to the scenario.

Question 1

Before Orchard hands the Odyssey service to operations, Leila must close verification item CHG-4480. A training campus is redesigning three overlapping 2.4-GHz cells. For 20-MHz operation in the U.S., which channel set avoids adjacent-channel overlap? Choose ONE.

  1. Channels 3, 6, and 9
  2. Channels 1, 6, and 11
  3. Channels 1, 4, and 8
  4. Channels 2, 7, and 12

Correct Answer: B

Correct Answer

 

 

Answer B is correct because In the 2.4-GHz band, Cisco guidance identifies 1, 6, and 11 as the three nonoverlapping 20-MHz channels used for a basic channel reuse plan. Assigning those three channels to adjacent cells minimizes adjacent-channel overlap compared with plans that use intermediate channel numbers. In the Before Orchard Odyssey validation, this distinction is directly relevant.

Incorrect Answers

 

Answer C is incorrect because Channels 4 and 8 overlap neighboring 20-MHz channels in the 2.4-GHz band. That plan creates adjacent-channel interference instead of using the established nonoverlapping set. That behavior is consistent with the configuration evidence supplied in the question.

Answer D is incorrect because These channel centers are offset from the standard 1/6/11 reuse plan and overlap other 2.4-GHz 20-MHz channels. They are not the nonoverlapping three-channel plan requested for the office. The device evaluates this property directly when it performs the relevant lookup or interface operation.

Answer A is incorrect because Although channel 6 is in the standard set, channels 3 and 9 overlap neighboring 20-MHz channels. The three APs would therefore contend with adjacent-channel energy rather than operating on separate nonoverlapping channels. In the Before Orchard Odyssey validation, this distinction is directly relevant.

 

Question 2

A peer review for Vantage at Quarry assigns Felix the evidence check recorded as CHG-4493. A mobile-device profile asks the administrator to enter the visible name of the employee wireless network. Which 802.11 identifier supplies that WLAN name? Choose ONE.

  1. RF channel width
  2. Encryption cipher
  3. SSID
  4. BSSID

Correct Answer: C

Correct Answer

 

 

Answer C is correct because The service set identifier is the logical WLAN name advertised or configured for clients and is what users commonly see when selecting a wireless network. A corporate SSID therefore provides the human-readable identity requested in the scenario. In the A Vantage Quarry validation, this distinction is directly relevant.

Incorrect Answers

 

Answer D is incorrect because A BSSID identifies a specific basic service set, commonly corresponding to an AP radio MAC address rather than the user-facing WLAN name. It is useful for distinguishing radios/cells but is not the requested human-readable network identifier. In the A Vantage Quarry validation, this distinction is directly relevant.

Answer A is incorrect because Channel width describes how much radio spectrum a transmission occupies, such as 20 or 40 MHz. It affects RF operation and throughput but does not name the WLAN for users. The scenario therefore hinges on the specific protocol behavior, not merely on a plausible value.

Answer B is incorrect because A cipher protects wireless frame confidentiality and integrity but is not the network name. Security and identification are separate properties, so the cipher cannot replace the SSID. This is the property an engineer would confirm during an implementation or troubleshooting check.

 

Question 3

The Rosewood branch is staging Circuit; Aya is completing the implementation checklist for CHG-4506. A warehouse tablet reads -50 dBm in an open aisle and -80 dBm after moving behind metal shelving, with no rise in channel utilization. What primarily caused the weaker signal? Choose ONE.

  1. SSID mismatch
  2. MAC address aging
  3. VRF route separation
  4. Attenuation through obstacles

Correct Answer: D

Correct Answer

 

 

Answer D is correct because RF energy is reduced as it propagates through distance and materials such as concrete; more-negative dBm values represent weaker received power. The large drop in received signal after moving behind walls is therefore consistent with attenuation. In the The Rosewood Circuit validation, this distinction is directly relevant.

Incorrect Answers

 

Answer A is incorrect because An SSID identifies the WLAN but does not physically reduce received RF power as a client moves behind obstacles. A mismatch could prevent association, but it would not explain the measured dBm change. In the The Rosewood Circuit validation, this distinction is directly relevant.

Answer B is incorrect because MAC aging removes inactive Layer 2 forwarding entries from a switch table after a timer expires. That forwarding-table behavior does not alter radio signal strength at the wireless receiver. The relevant state can be verified from the protocol information and configuration described here.

Answer C is incorrect because A VRF separates Layer 3 routing/forwarding tables on a network device. Routing-table separation has no direct effect on RF energy received through concrete walls. This result can be confirmed from the address, interface, or forwarding information provided. In the The Rosewood Circuit validation, this distinction is directly relevant.

 

Question 4

As part of Beacon readiness at Springdale, Layla investigates the condition logged in CHG-4519. An auditor wants wireless payloads protected from passive RF capture between a station and its access point. Which wireless function provides that protection? Choose ONE.

  1. Encryption
  2. SSID naming
  3. Channel selection
  4. MAC aging

Correct Answer: A

Correct Answer

 

 

Answer A is correct because Wireless encryption transforms protected frame contents so an observer without the appropriate key cannot simply read the traffic. That directly addresses confidentiality on the RF medium. The alternative fails because the operational result differs from what the scenario explicitly requires.

Incorrect Answers

 

Answer B is incorrect because An SSID identifies a WLAN and helps clients select it. Changing or hiding the name does not cryptographically protect frame contents from interception. The protocol rule makes this distinction observable during configuration validation and troubleshooting.

Answer C is incorrect because Choosing channels helps manage RF interference and capacity. It can improve reliability but does not make captured frame payloads confidential. The alternative would produce a different observable result during validation. This operational distinction is directly verifiable from the device state described in the scenario. In the As Beacon Springdale validation, this distinction is directly relevant.

Answer D is incorrect because MAC aging manages stale forwarding-table entries on switches. It neither encrypts wireless traffic nor prevents an RF observer from capturing frames. The correct choice aligns both with the configured state and with the resulting network behavior.

 

Question 5

Operations at Timberline asks Marta to validate Ion before approving change CHG-4532. A floor plan places adjacent 2.4-GHz cells on channels 1, 2, and 3, producing poor performance even at strong RSSI. Which remediation best reduces adjacent-channel interference? Choose ONE.

  1. Place all AP management interfaces in one VRF
  2. Move the APs to a reuse plan based on channels 1, 6, and 11
  3. Rename each SSID to a shorter value
  4. Increase MAC address aging time

Correct Answer: B

Correct Answer

 

 

Answer B is correct because Channels 1, 2, and 3 overlap heavily in 2.4 GHz, so neighboring cells contend with and interfere with one another. Using the standard nonoverlapping 1/6/11 set reduces adjacent-channel overlap and better matches enterprise RF design guidance. In the Operations Timberline Marta validation, this distinction is directly relevant.

Incorrect Answers

 

Answer C is incorrect because SSID length does not change the RF channel overlap between adjacent access points. The performance problem is caused by channel placement, not by the human-readable WLAN names. This distinction is what an engineer would verify from the resulting device state.

Answer D is incorrect because MAC aging affects wired Layer 2 forwarding-table retention. Changing that timer does not separate overlapping 2.4-GHz RF channels. This difference is important because the same device can treat otherwise similar values in different ways.

Answer A is incorrect because A VRF controls Layer 3 routing-table separation for IP traffic. It does not change the spectrum used by AP radios or eliminate adjacent-channel interference. The scenario tests that exact distinction as it would appear during a practical verification workflow.

 

Question 6

The Pulse deployment at Union has reached its verification gate; Ibrahim is handling CHG-4545. An integration host must preserve several legacy guest operating systems as separate managed machines while sharing the host’s CPU and memory resources. Which virtualization model should be used? Choose ONE.

  1. MAC address aging
  2. A wireless SSID
  3. Server virtualization with virtual machines
  4. A single Layer 2 VLAN

Correct Answer: C

Correct Answer

 

 

Answer C is correct because A hypervisor abstracts the physical server and presents isolated virtual hardware to multiple virtual machines, each of which can run its own guest operating system. That directly matches the requirement for independent guest OS instances sharing one physical host. In the The Pulse Union validation, this distinction is directly relevant.

Incorrect Answers

 

Answer D is incorrect because A VLAN partitions a switched Layer 2 broadcast domain but does not create virtual CPUs, memory, disks, or guest operating systems. Network segmentation alone cannot satisfy the server-compute virtualization requirement. The expected result follows from the device state and protocol semantics given in the question.

Answer A is incorrect because MAC aging controls how long dynamic Layer 2 forwarding entries remain in a switch table. It has no role in creating isolated guest operating systems on a physical server. The engineer must match the requested behavior, not just choose a value that is generally valid elsewhere.

Answer B is incorrect because An SSID identifies a wireless LAN to clients. It can map users into a network but does not virtualize server hardware or operating systems. This criterion is what separates the correct operational result from the other plausible alternatives.

 

Question 7

At the Valleyview office, Nora checks a Waypoint design assumption while processing CHG-4558. Developers need many portable microservice sandboxes with process and filesystem isolation but much less startup overhead than full guest operating systems. Which technology is appropriate? Choose ONE.

  1. Traditional virtual machines only
  2. VRF instances
  3. Ethernet MAC tables
  4. Containers

Correct Answer: D

Correct Answer

 

 

Answer D is correct because Containers isolate application processes and dependencies while sharing the host kernel, which reduces overhead compared with a full guest operating system per workload. That lightweight execution model matches the stated startup and kernel-sharing requirements. In the At Valleyview Nora validation, this distinction is directly relevant.

Incorrect Answers

 

Answer A is incorrect because A VM commonly includes a separate guest operating system above a hypervisor. That offers strong OS-level isolation but does not match the requirement to share the host kernel and avoid a guest OS per instance. In the At Valleyview Nora validation, this distinction is directly relevant.

Answer B is incorrect because VRFs create separate Layer 3 routing and forwarding tables within a network device. They isolate network routing domains rather than packaging application processes and dependencies. The network device applies this rule consistently when processing the described configuration or traffic.

Answer C is incorrect because MAC tables map destination MAC addresses to switch ports for Layer 2 forwarding. They provide switching state, not application workload isolation. The operational outcome follows directly from the configuration and protocol behavior described here.

 

Question 8

Change CHG-4571 covers the Dynamo network at Woodland, where Hugo is the assigned verifier. Production and test both use 10.10.10.0/24 on one router, but their routes must never collide. Which virtualization construct provides separate Layer 3 forwarding contexts? Choose ONE.

  1. VRF
  2. SSID
  3. MAC address aging
  4. Channel bonding

Correct Answer: A

Correct Answer

 

 

Answer A is correct because Virtual Routing and Forwarding creates separate routing and forwarding table instances on one Layer 3 device and can allow overlapping IP address space in different routing domains. That directly lets the two tenants use the same prefix without merging their routes. In the Change CHG-4571 Dynamo validation, this distinction is directly relevant.

Incorrect Answers

 

Answer B is incorrect because An SSID identifies a wireless LAN and may map wireless clients to other network constructs. It does not by itself create independent Layer 3 routing tables for overlapping tenant prefixes. The outcome is determined by the stated addressing or forwarding condition rather than by naming convention.

Answer C is incorrect because MAC aging removes inactive Layer 2 forwarding entries after a timer. It cannot isolate overlapping Layer 3 routes or create tenant-specific routing tables. This result can be confirmed from the address, interface, or forwarding information provided.

Answer D is incorrect because Wireless channel bonding combines spectrum to increase potential PHY throughput. It is an RF capacity feature and has no connection to routing-table virtualization. That makes the option unsuitable for this specific verification goal even if it is valid in another context.

 

Question 9

At Yorkfield, Owen validates the Kodiak cutover under change CHG-4584. A packet is received in VRF BLUE and no BLUE route matches. A matching route exists only in the global table. Which principle determines the lookup behavior? Choose ONE.

  1. SSID encryption blocks the route
  2. VRFs maintain separate routing and forwarding contexts
  3. Unknown unicasts are always flooded across VRFs
  4. Containers replace routing tables

Correct Answer: B

Correct Answer

 

 

Answer B is correct because A VRF associates interfaces with an independent routing/forwarding table, so a packet arriving in that context is looked up against the VRF unless explicit route leaking is configured. The global table is therefore not automatically consulted merely because it has a route. In the At Yorkfield Owen validation, this distinction is directly relevant.

Incorrect Answers

 

Answer C is incorrect because Unknown-unicast flooding is a Layer 2 behavior within a VLAN when a destination MAC is absent from the table. It does not cause Layer 3 packets to ignore VRF routing-table separation. In the At Yorkfield Owen validation, this distinction is directly relevant.

Answer D is incorrect because Containers isolate application workloads and do not inherently merge or replace router forwarding contexts. They cannot explain why a VRF lookup stays separate from the global routing table. This matters during verification because the configured value determines the device behavior being tested.

Answer A is incorrect because Wireless encryption protects frames over the RF medium. It has no role in selecting a router forwarding table for a packet already received on a VRF interface. The operational distinction is visible in the resulting interface, address, or forwarding state.

 

Question 10

The Raptor migration at Zephyr is in pre-check, and Lena owns ticket CHG-4597. A consolidation project moves four independent servers onto a single compute node while retaining a separate guest OS for each workload. What server-virtualization capability makes this possible? Choose ONE.

  1. The switch floods every destination MAC
  2. The AP advertises multiple SSIDs
  3. Multiple isolated virtual machines can share one physical server
  4. All applications must share one kernel namespace

Correct Answer: C

Correct Answer

 

 

Answer C is correct because Server virtualization abstracts CPU, memory, storage, and network resources so several VMs can coexist while retaining separate guest operating systems. That enables consolidation without forcing the legacy applications into one shared OS instance. In the The Raptor Zephyr validation, this distinction is directly relevant.

Incorrect Answers

 

Answer D is incorrect because Sharing one host kernel is characteristic of container-style isolation, not a requirement for independent legacy guest operating systems. It would conflict with the stated need to preserve each application server operating system. In the The Raptor Zephyr validation, this distinction is directly relevant.

Answer A is incorrect because Unknown-unicast flooding is a switching fallback when a destination MAC is not learned. It does not consolidate compute workloads or preserve separate guest operating systems. A correct implementation must satisfy that property rather than a superficially similar one.

Answer B is incorrect because Multiple SSIDs can provide distinct WLANs on wireless infrastructure. That is network-service virtualization, not server consolidation of independent operating systems. The requested outcome follows from the protocol rule being exercised in this scenario.

 

Question 11

During Amber’s Yield maintenance window, Tariq performs the network acceptance test for CHG-4610. A newly cleared switch receives a VLAN 30 frame on Gi1/0/7 whose source is 00:11:22:33:44:55. Which source-to-port association should appear in the dynamic MAC table? Choose ONE.

  1. Destination MAC is reachable through Gi1/0/7
  2. The IPv4 default gateway is Gi1/0/7
  3. The SSID for VLAN 30 is Gi1/0/7
  4. Source MAC 00:11:22:33:44:55 is reachable through Gi1/0/7 in VLAN 30

Correct Answer: D

Correct Answer

 

 

Answer D is correct because Ethernet switches populate their MAC address tables from the source MAC address of received frames, associating that source with the ingress port and VLAN. The received frame therefore teaches the switch where to send future frames destined to that source MAC. In the During Amber Yield validation, this distinction is directly relevant.

Incorrect Answers

 

Answer A is incorrect because A switch does not learn a destination location merely because a frame naming that destination arrived on another port. Dynamic learning is based on the source MAC observed on the ingress interface. In the During Amber Yield validation, this distinction is directly relevant.

Answer B is incorrect because Default gateways are Layer 3 next-hop addresses configured on hosts or represented by routed interfaces. A Layer 2 source-MAC observation does not create a default-gateway setting. That distinction prevents a valid-looking alternative from meeting the actual requirement.

Answer C is incorrect because An SSID is a wireless LAN identifier and is not learned from an Ethernet frame source address. The switching decision here concerns MAC-to-port learning in a VLAN, not wireless naming. This condition is observable in the resulting interface, addressing, or forwarding state.

 

Question 12

For ticket CHG-4623, Theo is reviewing the Fusion rollout at the Birch site. A known-unicast entry in VLAN 20 says 00:aa:bb:cc:dd:ee is reachable through Gi1/0/18. If the frame enters Gi1/0/4, where should the switch send it? Choose ONE.

  1. Forward the frame only toward Gi1/0/18
  2. Flood the frame to every forwarding port in VLAN 20
  3. Route the frame using the default gateway
  4. Drop the frame because it arrived on Gi1/0/4

Correct Answer: A

Correct Answer

 

 

Answer A is correct because For a known unicast destination, the switch looks up the destination MAC in the VLAN-specific table and forwards the frame out the associated port. Because the destination is already learned on Gi1/0/18, flooding is unnecessary. In the For CHG-4623 Theo validation, this distinction is directly relevant.

Incorrect Answers

 

Answer B is incorrect because Flooding is used for certain broadcast, multicast, or unknown-unicast conditions rather than for a valid known-unicast entry. The switch already knows the destination port, so sending copies everywhere would be unnecessary. In the For CHG-4623 Theo validation, this distinction is directly relevant.

Answer C is incorrect because Same-VLAN Layer 2 forwarding uses the MAC table and does not require a router simply because the frame traverses a switch. The destination is known locally at Layer 2. This is the relevant behavior an administrator would confirm before accepting the change. In the For CHG-4623 Theo validation, this distinction is directly relevant.

Answer D is incorrect because A frame is not dropped merely because its ingress port differs from the learned destination port. That difference is normal and tells the switch which egress interface to use. The device evaluates this property directly when it performs the relevant lookup or interface operation.

 

Question 13

Before Coral hands the Echo service to operations, Sara must close verification item CHG-4636. VLAN 40 receives a unicast frame whose destination MAC has never been learned. Which default forwarding behavior lets the unknown endpoint receive the frame? Choose ONE.

  1. Consult the DNS server for the MAC address
  2. Flood the frame out other forwarding ports in VLAN 40
  3. Send the frame to every port in every VLAN
  4. Discard every unknown unicast by default

Correct Answer: B

Correct Answer

 

 

Answer B is correct because When a unicast destination is unknown, the switch floods the frame within the same VLAN except back out the ingress port, allowing the destination to receive it if present. A reply then gives the switch an opportunity to learn the destination station as a source. In the Before Coral Echo validation, this distinction is directly relevant.

Incorrect Answers

 

Answer C is incorrect because VLANs define separate Layer 2 broadcast domains and MAC-table contexts. Unknown-unicast flooding stays within the frame VLAN rather than crossing all VLANs on the switch. The requested network outcome depends on this property being true in the current context.

Answer D is incorrect because Ordinary Ethernet switching normally floods an unknown unicast rather than discarding it outright. Dropping would prevent communication with a legitimate station whose MAC entry has not yet been learned or has aged out. In the Before Coral Echo validation, this distinction is directly relevant.

Answer A is incorrect because DNS resolves names to IP addresses and is not used by a switch to locate an unknown Layer 2 destination. The switch relies on flooding and subsequent source-MAC learning instead. The scenario therefore hinges on the specific protocol behavior, not merely on a plausible value.

 

Question 14

A peer review for Lumen at Driftwood assigns Rami the evidence check recorded as CHG-4649. A quiet workstation’s dynamic MAC entry aged out. Another endpoint sends to it before the workstation sources new traffic. What should the switch do with that first frame? Choose ONE.

  1. The switch creates a new IPv4 route
  2. The switch changes the workstation SSID
  3. The destination is treated as unknown and the frame is flooded within the VLAN
  4. The old port mapping is retained permanently

Correct Answer: C

Correct Answer

 

 

Answer C is correct because Aged dynamic entries are removed from the MAC table; until the destination is learned again, the switch has no specific egress port for that MAC. The first subsequent unknown-unicast frame is therefore flooded within the VLAN, excluding the ingress port. In the A Lumen Driftwood validation, this distinction is directly relevant.

Incorrect Answers

 

Answer D is incorrect because Dynamic MAC entries are specifically designed to age out after inactivity unless configured as static. The scenario states the entry has expired, so the switch cannot keep using that stale mapping as if it were permanent. In the A Lumen Driftwood validation, this distinction is directly relevant.

Answer A is incorrect because MAC aging operates at Layer 2 and does not add entries to the IP routing table. The forwarding fallback is a Layer 2 flood, not creation of a Layer 3 route. In the A Lumen Driftwood validation, this distinction is directly relevant.

Answer B is incorrect because An SSID is a wireless service identifier and is not derived from wired MAC-table aging. Aging only changes whether the switch remembers the MAC-to-port association. This is the property an engineer would confirm during an implementation or troubleshooting check.

 

Question 15

The Evergreen branch is staging Solstice; Max is completing the implementation checklist for CHG-4662. A bridge learns that a destination MAC resides on the same port where a frame just arrived. What should it do rather than transmit the frame back onto that segment? Choose ONE.

  1. Flood it to all other VLANs
  2. Send it to the default gateway
  3. Replace the destination MAC with the source MAC
  4. Filter it instead of forwarding it back out the same port

Correct Answer: D

Correct Answer

 

 

Answer D is correct because A switch uses the destination MAC table entry to select an egress port; when the known destination is on the same port as the source segment, forwarding the frame back to that port is unnecessary. Filtering avoids an invalid same-port retransmission. In the The Evergreen Solstice validation, this distinction is directly relevant.

Incorrect Answers

 

Answer A is incorrect because VLAN boundaries isolate Layer 2 forwarding domains, and a known same-port destination is not an unknown-unicast event. Flooding other VLANs would violate normal switching behavior. The relevant state can be verified from the protocol information and configuration described here.

Answer B is incorrect because A known same-segment Layer 2 destination does not require Layer 3 routing. The switch can decide locally from its MAC table and should not redirect the frame to a gateway. The alternative fails because the operational result differs from what the scenario explicitly requires.

Answer C is incorrect because Layer 2 switching forwards frames according to learned addresses; it does not rewrite the destination address merely because ingress and learned egress match. The correct behavior is filtering, not address substitution. In the The Evergreen Solstice validation, this distinction is directly relevant.

 

Question 16

As part of Zenith readiness at Forest, Kenji investigates the condition logged in CHG-4675. A small clinic has three neighboring 2.4-GHz APs. Which 20-MHz channel assignment best avoids adjacent-channel overlap? Choose ONE.

  1. Channels 1, 6, and 11
  2. Channels 1, 4, and 8
  3. Channels 2, 7, and 12
  4. Channels 3, 6, and 9

Correct Answer: A

Correct Answer

 

 

Answer A is correct because In the 2.4-GHz band, Cisco guidance identifies 1, 6, and 11 as the three nonoverlapping 20-MHz channels used for a basic channel reuse plan. Assigning those three channels to adjacent cells minimizes adjacent-channel overlap compared with plans that use intermediate channel numbers. In the As Zenith Forest validation, this distinction is directly relevant.

Incorrect Answers

 

Answer B is incorrect because Channels 4 and 8 overlap neighboring 20-MHz channels in the 2.4-GHz band. That plan creates adjacent-channel interference instead of using the established nonoverlapping set. The protocol rule makes this distinction observable during configuration validation and troubleshooting.

Answer C is incorrect because These channel centers are offset from the standard 1/6/11 reuse plan and overlap other 2.4-GHz 20-MHz channels. They are not the nonoverlapping three-channel plan requested for the office. That is the practical distinction the verification step is intended to expose.

Answer D is incorrect because Although channel 6 is in the standard set, channels 3 and 9 overlap neighboring 20-MHz channels. The three APs would therefore contend with adjacent-channel energy rather than operating on separate nonoverlapping channels. In the As Zenith Forest validation, this distinction is directly relevant.

 

Question 17

Operations at Glenwood asks Zoe to validate Glacier before approving change CHG-4688. A branch router hosts production and test networks that reuse the same RFC 1918 prefixes. What should isolate the Layer 3 routing contexts? Choose ONE.

  1. Channel bonding
  2. VRF
  3. SSID
  4. MAC address aging

Correct Answer: B

Correct Answer

 

 

Answer B is correct because Virtual Routing and Forwarding creates separate routing and forwarding table instances on one Layer 3 device and can allow overlapping IP address space in different routing domains. That directly lets the two tenants use the same prefix without merging their routes. In the Operations Glenwood Zoe validation, this distinction is directly relevant.

Incorrect Answers

 

Answer C is incorrect because An SSID identifies a wireless LAN and may map wireless clients to other network constructs. It does not by itself create independent Layer 3 routing tables for overlapping tenant prefixes. The alternative would produce a different observable result during validation.

Answer D is incorrect because MAC aging removes inactive Layer 2 forwarding entries after a timer. It cannot isolate overlapping Layer 3 routes or create tenant-specific routing tables. The correct choice aligns both with the configured state and with the resulting network behavior.

Answer A is incorrect because Wireless channel bonding combines spectrum to increase potential PHY throughput. It is an RF capacity feature and has no connection to routing-table virtualization. This difference is important because the same device can treat otherwise similar values in different ways.

 

Question 18

The Nimbus deployment at Heather has reached its verification gate; Ravi is handling CHG-4701. A switch receives a unicast frame for a destination MAC it has never learned in VLAN 22. Which forwarding action occurs by default? Choose ONE.

  1. Discard every unknown unicast by default
  2. Consult the DNS server for the MAC address
  3. Flood the frame out other forwarding ports in VLAN 40
  4. Send the frame to every port in every VLAN

Correct Answer: C

Correct Answer

 

 

Answer C is correct because When a unicast destination is unknown, the switch floods the frame within the same VLAN except back out the ingress port, allowing the destination to receive it if present. A reply then gives the switch an opportunity to learn the destination station as a source. In the The Nimbus Heather validation, this distinction is directly relevant.

Incorrect Answers

 

Answer D is incorrect because VLANs define separate Layer 2 broadcast domains and MAC-table contexts. Unknown-unicast flooding stays within the frame VLAN rather than crossing all VLANs on the switch. The scenario tests that exact distinction as it would appear during a practical verification workflow.

Answer A is incorrect because Ordinary Ethernet switching normally floods an unknown unicast rather than discarding it outright. Dropping would prevent communication with a legitimate station whose MAC entry has not yet been learned or has aged out. In the The Nimbus Heather validation, this distinction is directly relevant.

Answer B is incorrect because DNS resolves names to IP addresses and is not used by a switch to locate an unknown Layer 2 destination. The switch relies on flooding and subsequent source-MAC learning instead. The expected result follows from the device state and protocol semantics given in the question. In the The Nimbus Heather validation, this distinction is directly relevant.

 

Question 19

At the Ivory office, Nadia checks a Uplink design assumption while processing CHG-4714. An edge server must run several isolated microservices with lower overhead than separate guest operating systems. Which technology best fits? Choose ONE.

  1. Traditional virtual machines only
  2. VRF instances
  3. Ethernet MAC tables
  4. Containers

Correct Answer: D

Correct Answer

 

 

Answer D is correct because Containers isolate application processes and dependencies while sharing the host kernel, which reduces overhead compared with a full guest operating system per workload. That lightweight execution model matches the stated startup and kernel-sharing requirements. In the At Ivory Nadia validation, this distinction is directly relevant.

Incorrect Answers

 

Answer A is incorrect because A VM commonly includes a separate guest operating system above a hypervisor. That offers strong OS-level isolation but does not match the requirement to share the host kernel and avoid a guest OS per instance. In the At Ivory Nadia validation, this distinction is directly relevant.

Answer B is incorrect because VRFs create separate Layer 3 routing and forwarding tables within a network device. They isolate network routing domains rather than packaging application processes and dependencies. The engineer must match the requested behavior, not just choose a value that is generally valid elsewhere.

Answer C is incorrect because MAC tables map destination MAC addresses to switch ports for Layer 2 forwarding. They provide switching state, not application workload isolation. The implementation must match this protocol property to satisfy the scenario’s requirement.

 

Question 20

Change CHG-4727 covers the Bridge network at Jasper, where Mira is the assigned verifier. A host sends its first Ethernet frame into Gi1/0/3 in VLAN 12 with source MAC 68:7f:74:12:34:56. What does the switch learn? Choose ONE.

  1. Source MAC 68:7f:74:12:34:56 is reachable through Gi1/0/3 in VLAN 12
  2. Destination MAC is reachable through Gi1/0/7
  3. The IPv4 default gateway is Gi1/0/7
  4. The SSID for VLAN 30 is Gi1/0/7

Correct Answer: A

Correct Answer

 

 

Answer A is correct because Ethernet switches populate their MAC address tables from the source MAC address of received frames, associating that source with the ingress port and VLAN. The received frame therefore teaches the switch where to send future frames destined to that source MAC. In the Change CHG-4727 Bridge validation, this distinction is directly relevant.

Incorrect Answers

 

Answer B is incorrect because A switch does not learn a destination location merely because a frame naming that destination arrived on another port. Dynamic learning is based on the source MAC observed on the ingress interface. In the Change CHG-4727 Bridge validation, this distinction is directly relevant.

Answer C is incorrect because Default gateways are Layer 3 next-hop addresses configured on hosts or represented by routed interfaces. A Layer 2 source-MAC observation does not create a default-gateway setting. This distinction is what an engineer would verify from the resulting device state.

Answer D is incorrect because An SSID is a wireless LAN identifier and is not learned from an Ethernet frame source address. The switching decision here concerns MAC-to-port learning in a VLAN, not wireless naming. This criterion is what separates the correct operational result from the other plausible alternatives.

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