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Exam Code: N10-009
Exam Name: CompTIA Network+
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CompTIA Network+ N10-009 Practice Test 20

Question 190

A link between routers needs exactly two IPv4 interface addresses and supports /31. Which diagnostic or verification check MOST directly evaluates the expected network behavior in this situation?

  1. Expect a directed-broadcast service at one of the /31 endpoint addresses
  2. Verify both endpoints can exchange packets without broadcast address semantics
  3. Confirm only one endpoint can ping its own loopback rather than the peer
  4. Evaluate link speed but not IP reachability between both /31 endpoints

Explanation

Correct Answer

B:

/31 point-to-point use is supported, unlike traditional multipoint subnet assumptions. The result of the remedy is checked directly: Verify both endpoints can exchange packets without broadcast address semantics.

Incorrect Answers

A:

Expect a directed-broadcast service at one of the /31 endpoint addresses. /31 point-to-point use is supported, unlike traditional multipoint subnet assumptions. The appropriate acceptance test is: Verify both endpoints can exchange packets without broadcast address semantics.

C:

Confirm only one endpoint can ping its own loopback rather than the peer. /31 point-to-point use is supported, unlike traditional multipoint subnet assumptions. The appropriate acceptance test is: Verify both endpoints can exchange packets without broadcast address semantics.

D:

Evaluate link speed but not IP reachability between both /31 endpoints. /31 point-to-point use is supported, unlike traditional multipoint subnet assumptions. The appropriate acceptance test is: Verify both endpoints can exchange packets without broadcast address semantics.

Question 191

A project proposes 192.168.9.64/26 with first host .64. Which response MOST directly addresses the stated network problem or requirement?

  1. Assign 192.168.9.64 as the first workstation on 192.168.9.64/26
  2. Assign 192.168.9.127 as a conventional end-host address for that same block
  3. Identify .64 as network address and choose a usable host within block
  4. Use 192.168.9.128 as an additional host inside 192.168.9.64/26

Explanation

Correct Answer

C:

Base subnet address is not a conventional usable host address. A direct way to confirm the outcome is to enumerate /26 network, broadcast and host addresses.

Incorrect Answers

A:

Assign 192.168.9.64 as the first workstation on 192.168.9.64/26. Base subnet address is not a conventional usable host address. This does not implement the needed approach: identify .64 as network address and choose a usable host within block.

B:

Assign 192.168.9.127 as a conventional end-host address for that same block. Base subnet address is not a conventional usable host address. This does not implement the needed approach: identify .64 as network address and choose a usable host within block.

D:

Use 192.168.9.128 as an additional host inside 192.168.9.64/26. Base subnet address is not a conventional usable host address. This does not implement the needed approach: identify .64 as network address and choose a usable host within block.

Question 192

A project proposes 192.168.9.64/26 with first host .64. Which diagnostic or verification check MOST directly evaluates the expected network behavior in this situation?

  1. List the .64 network address as the first usable host in the /26
  2. Count .127 as a regular host rather than its subnet broadcast address
  3. Check a DHCP service is running without calculating the .65 through .126 usable range
  4. Enumerate /26 network, broadcast and host addresses

Explanation

Correct Answer

D:

Base subnet address is not a conventional usable host address. The result of the remedy is checked directly: Enumerate /26 network, broadcast and host addresses.

Incorrect Answers

A:

List the .64 network address as the first usable host in the /26. Base subnet address is not a conventional usable host address. The appropriate acceptance test is: Enumerate /26 network, broadcast and host addresses.

B:

Count .127 as a regular host rather than its subnet broadcast address. Base subnet address is not a conventional usable host address. The appropriate acceptance test is: Enumerate /26 network, broadcast and host addresses.

C:

Check a DHCP service is running without calculating the .65 through .126 usable range. Base subnet address is not a conventional usable host address. The appropriate acceptance test is: Enumerate /26 network, broadcast and host addresses.

Question 193

A monitoring device configured 10.10.5.127/25 cannot reach its LAN. Which response MOST directly addresses the stated network problem or requirement?

  1. Recognize .127 is the broadcast address of 10.10.5.0/25
  2. Keep 10.10.5.127 as a conventional host address on 10.10.5.0/25
  3. Treat .127 as the network identifier of the following 10.10.5.128/25 block
  4. Enlarge the DNS cache rather than correct the interface's broadcast-address use

Explanation

Correct Answer

A:

Broadcast address depends on the actual prefix length. A direct way to confirm the outcome is to verify mask and assigned host range before changing gateway.

Incorrect Answers

B:

Keep 10.10.5.127 as a conventional host address on 10.10.5.0/25. Broadcast address depends on the actual prefix length. This does not implement the needed approach: recognize .127 is the broadcast address of 10.10.5.0/25.

C:

Treat .127 as the network identifier of the following 10.10.5.128/25 block. Broadcast address depends on the actual prefix length. This does not implement the needed approach: recognize .127 is the broadcast address of 10.10.5.0/25.

D:

Enlarge the DNS cache rather than correct the interface's broadcast-address use. Broadcast address depends on the actual prefix length. This does not implement the needed approach: recognize .127 is the broadcast address of 10.10.5.0/25.

Question 194

A monitoring device configured 10.10.5.127/25 cannot reach its LAN. Which diagnostic or verification check MOST directly evaluates the expected network behavior in this situation?

  1. Count .127 in the assignable host interval for a /25 starting at .0
  2. Verify mask and assigned host range before changing gateway
  3. Interpret the successful ARP response to a separate machine as proof .127 is usable
  4. Check only the routing metric without confirming the interface's masked broadcast boundary

Explanation

Correct Answer

B:

Broadcast address depends on the actual prefix length. The result of the remedy is checked directly: Verify mask and assigned host range before changing gateway.

Incorrect Answers

A:

Count .127 in the assignable host interval for a /25 starting at .0. Broadcast address depends on the actual prefix length. The appropriate acceptance test is: Verify mask and assigned host range before changing gateway.

C:

Interpret the successful ARP response to a separate machine as proof .127 is usable. Broadcast address depends on the actual prefix length. The appropriate acceptance test is: Verify mask and assigned host range before changing gateway.

D:

Check only the routing metric without confirming the interface's masked broadcast boundary. Broadcast address depends on the actual prefix length. The appropriate acceptance test is: Verify mask and assigned host range before changing gateway.

Question 195

An address 192.168.10.250/23 must reach 192.168.11.10. Which response MOST directly addresses the stated network problem or requirement?

  1. Put 192.168.11.10 behind a router only because its third octet differs from .10
  2. Reconfigure both interfaces to /25 without an approved segmentation requirement
  3. Treat both hosts as on the same /23 if topology matches
  4. Claim that 192.168.10.250/23 belongs to 192.168.10.0/24 rather than 192.168.10.0/23

Explanation

Correct Answer

C:

Classless /23 boundaries cross an apparent dotted-decimal /24. A direct way to confirm the outcome is to apply bitwise mask and test ARP for remote endpoint.

Incorrect Answers

A:

Put 192.168.11.10 behind a router only because its third octet differs from .10. Classless /23 boundaries cross an apparent dotted-decimal /24. This does not implement the needed approach: treat both hosts as on the same /23 if topology matches.

B:

Reconfigure both interfaces to /25 without an approved segmentation requirement. Classless /23 boundaries cross an apparent dotted-decimal /24. This does not implement the needed approach: treat both hosts as on the same /23 if topology matches.

D:

Claim that 192.168.10.250/23 belongs to 192.168.10.0/24 rather than 192.168.10.0/23. Classless /23 boundaries cross an apparent dotted-decimal /24. This does not implement the needed approach: treat both hosts as on the same /23 if topology matches.

Question 196

An address 192.168.10.250/23 must reach 192.168.11.10. Which diagnostic or verification check MOST directly evaluates the expected network behavior in this situation?

  1. Compare the hosts using /24 masks even though both are configured for /23
  2. Require a default-gateway hop when the same /23 can resolve directly by ARP
  3. Treat matching first three octets as the only possible test of common-subnet membership
  4. Apply bitwise mask and test ARP for remote endpoint

Explanation

Correct Answer

D:

Classless /23 boundaries cross an apparent dotted-decimal /24. The result of the remedy is checked directly: Apply bitwise mask and test ARP for remote endpoint.

Incorrect Answers

A:

Compare the hosts using /24 masks even though both are configured for /23. Classless /23 boundaries cross an apparent dotted-decimal /24. The appropriate acceptance test is: Apply bitwise mask and test ARP for remote endpoint.

B:

Require a default-gateway hop when the same /23 can resolve directly by ARP. Classless /23 boundaries cross an apparent dotted-decimal /24. The appropriate acceptance test is: Apply bitwise mask and test ARP for remote endpoint.

C:

Treat matching first three octets as the only possible test of common-subnet membership. Classless /23 boundaries cross an apparent dotted-decimal /24. The appropriate acceptance test is: Apply bitwise mask and test ARP for remote endpoint.

Question 197

A /30 transit network is mistakenly assigned four end hosts. Which response MOST directly addresses the stated network problem or requirement?

  1. Resize or split the subnet according to usable address count
  2. Assign four conventional end-host interfaces to the four addresses in a single /30
  3. Treat the /30 broadcast endpoint as a third assignable customer host
  4. Use the /30 network identifier as an additional routable client address

Explanation

Correct Answer

A:

Network and broadcast consume two of the four /30 addresses. A direct way to confirm the outcome is to count the two conventional usable host addresses in /30.

Incorrect Answers

B:

Assign four conventional end-host interfaces to the four addresses in a single /30. Network and broadcast consume two of the four /30 addresses. This does not implement the needed approach: resize or split the subnet according to usable address count.

C:

Treat the /30 broadcast endpoint as a third assignable customer host. Network and broadcast consume two of the four /30 addresses. This does not implement the needed approach: resize or split the subnet according to usable address count.

D:

Use the /30 network identifier as an additional routable client address. Network and broadcast consume two of the four /30 addresses. This does not implement the needed approach: resize or split the subnet according to usable address count.

Question 198

A /30 transit network is mistakenly assigned four end hosts. Which diagnostic or verification check MOST directly evaluates the expected network behavior in this situation?

  1. Claim /30 provides four usable hosts because its address count is four
  2. Count the two conventional usable host addresses in /30
  3. Validate only the configured default route without counting reserved subnet addresses
  4. Check a single working host and infer that two more ordinary hosts can use the /30

Explanation

Correct Answer

B:

Network and broadcast consume two of the four /30 addresses. The result of the remedy is checked directly: Count the two conventional usable host addresses in /30.

Incorrect Answers

A:

Claim /30 provides four usable hosts because its address count is four. Network and broadcast consume two of the four /30 addresses. The appropriate acceptance test is: Count the two conventional usable host addresses in /30.

C:

Validate only the configured default route without counting reserved subnet addresses. Network and broadcast consume two of the four /30 addresses. The appropriate acceptance test is: Count the two conventional usable host addresses in /30.

D:

Check a single working host and infer that two more ordinary hosts can use the /30. Network and broadcast consume two of the four /30 addresses. The appropriate acceptance test is: Count the two conventional usable host addresses in /30.

Question 199

The network team needs independent /26 networks from one /24. Which response MOST directly addresses the stated network problem or requirement?

  1. Create /26 subnets starting at .0, .32, .64 and .96 in the same /24
  2. Divide the /24 into four /25 blocks that must overlap
  3. Split into four contiguous /26 prefixes without overlap
  4. Reuse the 192.168.x.63 broadcast address as the start of the next /26 subnet

Explanation

Correct Answer

C:

Subnet boundary stride follows block size. A direct way to confirm the outcome is to verify prefix boundaries at 0,64,128,192 in final octet.

Incorrect Answers

A:

Create /26 subnets starting at .0, .32, .64 and .96 in the same /24. Subnet boundary stride follows block size. This does not implement the needed approach: split into four contiguous /26 prefixes without overlap.

B:

Divide the /24 into four /25 blocks that must overlap. Subnet boundary stride follows block size. This does not implement the needed approach: split into four contiguous /26 prefixes without overlap.

D:

Reuse the 192.168.x.63 broadcast address as the start of the next /26 subnet. Subnet boundary stride follows block size. This does not implement the needed approach: split into four contiguous /26 prefixes without overlap.

Question 200

The network team needs independent /26 networks from one /24. Which diagnostic or verification check MOST directly evaluates the expected network behavior in this situation?

  1. Count five nonoverlapping /26s inside one /24
  2. Treat final-octet .32 and .96 as valid /26 starting boundaries
  3. Confirm four VLAN labels exist without checking that their /26 prefix ranges do not overlap
  4. Verify prefix boundaries at 0,64,128,192 in final octet

Explanation

Correct Answer

D:

Subnet boundary stride follows block size. The result of the remedy is checked directly: Verify prefix boundaries at 0,64,128,192 in final octet.

Incorrect Answers

A:

Count five nonoverlapping /26s inside one /24. Subnet boundary stride follows block size. The appropriate acceptance test is: Verify prefix boundaries at 0,64,128,192 in final octet.

B:

Treat final-octet .32 and .96 as valid /26 starting boundaries. Subnet boundary stride follows block size. The appropriate acceptance test is: Verify prefix boundaries at 0,64,128,192 in final octet.

C:

Confirm four VLAN labels exist without checking that their /26 prefix ranges do not overlap. Subnet boundary stride follows block size. The appropriate acceptance test is: Verify prefix boundaries at 0,64,128,192 in final octet.

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